find dy/dx of
y=(root(a square + xsqu.) + root(a squ. - xsqu.))/(root a squ. + root x squ.)-(root a squ. - x squ.)
Is it dy/dx = a2/(x3)(1-y2).
Plz reply back.
Plz reply back.
ans is correst
i tried to put x2=a2cos2theta
but culdnt getit
also tried rationalising but didnt get in the same form as required
i am getting
dy/dx=4a2y2/(x3)(1-y2)
i dont know how to simplify it from here. can you tell me...i know this is a late reply but i have recently joined the forum.
Please reply.
dy/dx=4a2y2/(x3)(1-y2)
i dont know how to simplify it from here. can you tell me...i know this is a late reply but i have recently joined the forum.
Please reply.
U must have done some mistake in taking derivative. There is no 4y2 in the ans. The rest of ans. is correct. No need to simplify further, though u may do it by putting value of y2.
I am getting dy/dx=-2/[1+cos(theta)]^2 where x^2=a^2sin(theta).
First i rationalised and then substituted x^2=a^2sin(theta).