HELLO FRIENDS,
PLEASE SOLVE THIS PROBLEM.
There is a charged ring of radius R which is charged uniformly with a charge Q.A sphere of equal radius R is constucted with its center on the circumference on the ring.What will be the electric flux through this sphere.
thank you.
Electric flux = Charge Inside/Epsilon
=(2/2pi)*Q/epsilon
= Q/ pi * epsilon.
I think so.
=(2/2pi)*Q/epsilon
= Q/ pi * epsilon.
I think so.
OPEN PAGE 130 OF H.C. VERMA PART 2 AND U WILL GET YOUR ANSWER.
WHY DON'T U READ THAT BOOK CAREFULLY? EVERY IITJEE QUESTION IS A VARIANT OF SOME QUESTION OF HC VERMA. SO I WOULD SAY DO IT.
WHY DON'T U READ THAT BOOK CAREFULLY? EVERY IITJEE QUESTION IS A VARIANT OF SOME QUESTION OF HC VERMA. SO I WOULD SAY DO IT.
The charge present inside the sphere is Q/3.
From the geometry of the figure you will see that the arc inside the sphere subtends an angle of 2pi/3.
So taking the ratio of 2pi/3 and 2pi ,you get Q/3 inside the sphere.
The flux entering due to the charge on the rest of the ring is equal to the flux leaving due to the same.
hence the flux calculated will be due to the charge inside alone.
that is Q/3(epselon)
I dont know for sure though.