if in limits both the numerator and denominator are turning out to be zero i.e. 0/0 form then the numerator and denominator are differentiated individually and the limit is found.
if this to is of 0/0 form the process must be continued till the 0/0 form is not obtained.
please note that infinity/infinity must be converted to 0/0.
example:
limit (sin(x)-x)/sin(x)
x->0
=
limit (cos(x)-1)/cos(x) = 0
x->0
if this to is of 0/0 form the process must be continued till the 0/0 form is not obtained.
please note that infinity/infinity must be converted to 0/0.
example:
limit (sin(x)-x)/sin(x)
x->0
=
limit (cos(x)-1)/cos(x) = 0
x->0
mate,
u're probabely gonna get it in any good books.
its like in a limit in the form a/b where a n b are te func of x it the limit is in the 0 by 0 form i.e by puttin the limiting value in the numerator n the denominater we get 0/0 form the limit is solved by deriving the numerator n denominater separately .then if its still in the 0/0 form just continue doin it untill the ans is got . but ber sure to check whether the limit atll exists or not at the given limiting value before proceedin to do the limit in the 1st place
u're probabely gonna get it in any good books.
its like in a limit in the form a/b where a n b are te func of x it the limit is in the 0 by 0 form i.e by puttin the limiting value in the numerator n the denominater we get 0/0 form the limit is solved by deriving the numerator n denominater separately .then if its still in the 0/0 form just continue doin it untill the ans is got . but ber sure to check whether the limit atll exists or not at the given limiting value before proceedin to do the limit in the 1st place