A thin uniform heavy rod of length L hangs from a horizontal axis through one end.what is the minimum angular velocity that must be imparted to rotate it through a right angle
hi friend,
Considering the mass of the rod to be uniform, the velocity that is needed to rotate it by right angle can be produced from the KE...
the KE = the PE lost by the rod in its motion
so the loss in PE is M*g*dispacement of centre of mass of rod
=M*g*L/2=1/2Mv^2
therefore gL=v^2
V=gl^1/2
the KE = the PE lost by the rod in its motion
so the loss in PE is M*g*dispacement of centre of mass of rod
=M*g*L/2=1/2Mv^2
therefore gL=v^2
V=gl^1/2
v/l=(g/l)^.5
threrfore the required angular velocity is (g/L)^.5