Dear friends please solve this 4 me whether it is too easy for you
Q-- find the equation of a circle whose radius is 5 and which touches the circle x2+y2-2x-4y-20=0 at the point (5,5).
good luck
hi friend,
the centre of that given circle is A[1,2} and radius is 5
point of contact is [5,5].If B{h,k} be the centre of the required circle with radius 5 ..then the point of contact will be the mid point of AB
5=h+1/2 and 5=k+2/2
u get h=9 and k=8
so the equation will be [x-9]^2 + [y-8]^2 = 5^2
wishing u all the very best