This message was originally posted by Akash Sharma
question
There are ‘n’ no. of batteries connected in series in a closed circuit such that the emf of each battery is denoted by e (i) .Each battery has its own internal resistance r(i).Given that r(i) = ke (i),such that ‘k’ is a constant.we are to find the current in the circuit if no other resistance than that of internal resistance of batteries is present. Also there is no other source of potential difference other than that through batteries.
But my question is not this
Current through the circuit is
I= S e (i) / S r(i)
=1/k Ü
accordingly a constant current is established in the circuitBut when we find the potential difference across ith battery it comes out to be
V (i)= e (i) - Ir(i)
=e (i) - I/k*k*e (i) \ givenÞ r(i)=ke (i)
=e (i) -e (i)
=0
Now the question is
HOW IS THE CURRENT FLOWING IN THE CIRCUIT IF THE POTENTIAL OF EACH BATTERY IN THE CIRCUIT IS ZERO AS THERE IS NOTHING ELSE CONNECTED IN THE CIRCUIT OTHER THAN GIVEN BATTERIES?
(FOR THIS QUESTION REFER CONCEPTS OF PHYSICS(2)H.C. VERMA PAGE NO 188 QUESTION NO. 8)
DO ANSWER THIS QUESTION
AKASH