A sample of impure Magnesium is reacted with diluted Sulphuric Acid to give the respective salt and Hydrogen.If 1 gram of impure sample gave 298.6 cc of Hydrogen at STP.Calculate the % purity of the sample (MAgnesium = 24,Hydrogen = 1)
Mg + H2SO4 >>> MgSO4 + H2
298.6 cc hydrogen means 13.3 * 10^(-3) moles of hydrogen & that much mole of hydrogen will be formed by 13.3 * 10^(-3) moles & which have 13.3 * 10^(-3) * 24 = 0.319 gram weight
% purity = (0.319/1) * 100 = 31.9% Answer