Physics - Kinematics by Krishnan G - Friday, 10 May 2013, 9:58 PM Number of replies: 1 From a certain tower of unknown height, it is found that the maximum range of R at a certain projection velocity u is obtained for a projection angle of θ. Derive u in terms of R, g and θ. Answer is given as u = √ [ R g tan θ ] Please expalin. Permalink Reply In reply to Krishnan G Re: Physics - Kinematics by Manish Verma - Sunday, 26 May 2013, 7:44 PM Hint is attached as image file. Forum-Physics-Kinematics.png Permalink Show parent Reply
In reply to Krishnan G Re: Physics - Kinematics by Manish Verma - Sunday, 26 May 2013, 7:44 PM Hint is attached as image file. Forum-Physics-Kinematics.png Permalink Show parent Reply
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