I am having a doubt in Electrostatics.
Is the magnitude of electric field constant over an equipotential surface?
Please tell me.
E = -dV/dr ( v = constant)
hence , dV/dr=0
so field over equipotential surface = 0
Let us move by a small distance dr along equipotential surface.
Undetermined error: @@E_r = -dV/dr@@
Since there is no change in V, Er=0.
However, nothing can be said about the other components of the field. Hence, in general it cannot be inferred that electric field is constant.
Undetermined error: @@E_r = -dV/dr@@
Since there is no change in V, Er=0.
However, nothing can be said about the other components of the field. Hence, in general it cannot be inferred that electric field is constant.