hi sirs/madam
a liquid occupies half of a vessel at a particular temperature. the volume of the unoccupied part remaints constant at all temperature if alpha and gama are coefficients of linear and real expansion of a vessel and liquid, then gama equal to ...
kindly request you to give the solution with steps and thank you
γ can be obtained from the following:
Vol. of liquid after temperature change=V(1+3α.ΔT)-V/2=V/2(1+γ.ΔT), where
V=Initial vol. of vessel.
Let us suppose the volume of the vessel be v so the volume occupied by the liquid is v/2..
Now if increase the temperature by x
if alpha is the linear expansion of the vessel then 3 *alpha is the volumic expansion of the vessel.
now new volume of the vessel
v(1+3*alpha*x)
and new volume of the liquid
=v/2(1+gamma*x) (coeffecient of real expansion or volume expansion of the liquid is gamma)
=v(1+3*alpha*x)-v/2(1+gamma*x)=k(as in the question) k=constant
v(1+3*alpha*x)-v/2(1+gamma*x)=v/2
v+3alphavx-v/2-v/2gammax=v/2
v(1+3alphax-1/2-1/2gammax)=v/2
1+3alphax-1/2-1/2gammax=1/2
1+3alphax-1/2gammax=1
=3alphax=1/2gammax
6alphax=gammax
6alpha=gamma
a student of class 10. Here coeffecient of real expansion or(volume expansion)