At 100degreeC and 1 atm, if the density of liquid water is 1.0g/cm^3 and that of water vapour is 0.0006g/cm^3, then the volume occupied by water molecules in 1L of steam at that temperature is
a 6cm^3
b 60cm^3
c 0.6cm^3
d 0.06cm^3
1L=1000 cm3
1L steam contains 0.0006x1000=0.6 gm water
Volume of molecules = 0.6/1.0 = 0.6 cm3