, find the number of terms and the series.Thank You!
Let the total no. of terms = 2n; common diff. = d
Given,
24 = n/2 [ 2a + (n-1)(2d) ]
30 = n/2 [ 2(a+d) + (n-1)(2d) ]
a + (2n-1)d = a + 10.5
On solving these eq. we get ;
a=1.5 ; n=4 ; thus, 2n = 8 ; d=1.5
So the series is = 1.5, 3, 4.5...
No. of terms in the series is 8
first term=3/2
common difference=3/2
hence ,
series = 3/2 , 3 , 9/2 , 6 , 15/2 , 9 , 21/2 , 12/span>
first term=3/2
common difference=3/2
hence ,
series = 3/2 , 3 , 9/2 , 6 , 15/2 , 9 , 21/2 , 12/span>