Q.1.A beam of electrons accelerated with 4.64 V was passed through a tube having mercury vapours .As a result of absorption,electronic changes occured with mercury atoms and light was emitted.If the full energy of the single electron ws converted into light ,what was the wave number of emitted light.
Q.2.The binding energy of an electron in the ground state of an atom is equal to 24.6eV.Find the enegry required to remove both electrons from the atom.
Q.1: eV=hf
f=c/lambda
Wave number can be obtained.
Q.2: Since question says both the electrons, assuming the atom is He, after the first electron is removed, Bohr's model would be applicable for calculating the binding energy. Total energy = Sum of the two binding energies.