Please answer the question below.
Thank you!
Forum_Post_Question_1.JPG
Given, \(sin\theta=1-sin^2\theta=cos^2\theta\)
Now using power reduction in the given expression,
\(sin^6\theta+3sin^5\theta+3sin^4\theta+sin^3\theta+sin^2\theta+3cos^2\theta+2sin^2\theta\)
=\(sin^6\theta+3sin^5\theta+3sin^4\theta+sin^3\theta+3\)
=\((sin^2\theta+sin\theta)^3+3\)
Now, one can proceed further.
Now using power reduction in the given expression,
\(sin^6\theta+3sin^5\theta+3sin^4\theta+sin^3\theta+sin^2\theta+3cos^2\theta+2sin^2\theta\)
=\(sin^6\theta+3sin^5\theta+3sin^4\theta+sin^3\theta+3\)
=\((sin^2\theta+sin\theta)^3+3\)
Now, one can proceed further.
Thank you very much sir.