If p1 and p2 are the lengths of the normals drawn from the origin on the lines
xcosΘ + ysinΘ = 2acos4Θ and xsecΘ + ycosecΘ = 4acos2Θ respectively and
mp12 + np22 = 4a2, then find the value of m and n.
On solving mcos2(4theta)+(n/4)sin2(4theta)=1
Comparing it with cos2(4theta)+sin2(4theta)=1
m=1 and n=4