For the translation of centre of mass: F - f = Ma
Here, f is the frictional force.
For rotation, \(F.R + f.R = I\alpha\)
Mention of pure rolling in the question lets you connect translational and rotational motions.
So, we have \(a=R\alpha\).
For the translation of centre of mass: F - f = Ma
Here, f is the frictional force.
For rotation, \(F.R + f.R = I\alpha\)
Mention of pure rolling in the question lets you connect translational and rotational motions.
So, we have \(a=R\alpha\).