Stoichiometry by Mohit Tiwari - Friday, 30 May 2008, 12:24 PM Number of replies: 1 How much BaCl2 would be needed to make 250 ml of a solution having same concentration of Cl- as the one containing 3.78 g of NaCl per 100 ml? Permalink Reply In reply to Mohit Tiwari Re: Stoichiometry by Srinath Murthy - Saturday, 31 May 2008, 12:07 AM [Cl-] in NaCl=(3.78/58.5)/0.1 [Cl-] in BaCl2=(w/207)/0.25 Just solve for w equating the two above. Permalink Show parent Reply
In reply to Mohit Tiwari Re: Stoichiometry by Srinath Murthy - Saturday, 31 May 2008, 12:07 AM [Cl-] in NaCl=(3.78/58.5)/0.1 [Cl-] in BaCl2=(w/207)/0.25 Just solve for w equating the two above. Permalink Show parent Reply