Permutations by Chandni Bhatia - Tuesday, 30 October 2007, 10:15 AM Number of replies: 1 How many natural numbers not exceeding 4321 can be formed with the digits 1,2,3 and 4 ,if the digits can repeat? Answer is 313. Permalink Reply In reply to Chandni Bhatia Re: Permutations by lokesh sardana - Friday, 2 November 2007, 12:07 PM First calculate total nos. formed by digits 1,2,3,4 which will come out to be 340.Then find the nos. which are greater then 4321 which will come out to be 27.Finally subtract to get final result which is 340-27=313 Permalink Show parent Reply
In reply to Chandni Bhatia Re: Permutations by lokesh sardana - Friday, 2 November 2007, 12:07 PM First calculate total nos. formed by digits 1,2,3,4 which will come out to be 340.Then find the nos. which are greater then 4321 which will come out to be 27.Finally subtract to get final result which is 340-27=313 Permalink Show parent Reply