a) Obtain an expression for d in terms of n and R such that the ray intersects the diameter at the point of emergence.
b) What is the allowed range of values of n for the above possibility to occur??
This ques. came in this year's Indian National Physics Oly. Plzzzz try solving this ques. and tell me the answer.
I got the answer as d = [nR(4-n2)1/2]/2
and the allowed range of n as (1,2).
Well Ankul I got the samething
d=[nR(4-n2)1/2]/2 & about n obvously (1,2)
Well the result is consistent with the limitations of as if u observe always d<R equality occuring iff n=21/2
More over total internal reflection is absent. May be u did observe all this .Its such simple one any ways why did someone like u ask this.
Anyways what troubles u MAN
Otherwise i also tried it myself 3-4 times and couldn't find any mistake...
Thnxxxxx man for the reply
Well one more thing.... shall we include n=1 and 2 in the range of n or not.....
Because for n = 2... d = 0 and for n = 1..... d is not = 0 which should be the case otherwise... what do you say??
Sorry for the late reply man just got busy
Anyways if n=2 is included then i think we need to inclde every number greater than 1 as a solution keepin d=0 which is obviously dumb so I dont recomend 2 thats the reason for the open interval in my answer .I too did observe that n=1 is givin something stupid acually while solvin I was forced to make an assumption tht n is different from 1 and after getting the solution obvously u wil check for extreme values as they do matter a lot hence n=1 is rejected. So i would say N belogs to(1,2)
Ayways da i am quite impressed by the way u and chandni
Reason out ur answers(I was referrin to older disscussions)
This ques. doesn't seems to be that easy..... dont know the exact reason but some ppl r saying that the answer should be (21/2 to 2). Lemme confirm it how they were getting root 2 in the picture.... some were saying that the formula would not be valid for n above 1 and below 21/2.
I wud request u to think over the situation again. Actually while simplifying for d in terms of n and R we actually square both the sides 2 times.... i think u wud have also done that.... so that way some extra roots would also be coming.... well n = 1 is one such root.... i think other roots are okey.... still i wud fix myself wid (1,2)... but just check it once again...
Ya dude thts right we are invitinng unnessasary solutions into our equations by squarin
I got somethin like this
(R2-d2)1/2=R(n2-2)/2
Which we further square 2 arrive at ur final answer but the thing here is R.H.S has 2 be +ve as L.H.S is +ve
Hence before squarin itself we need 2 observe that n should not be less than 21/2.
well i didnt observe all this as i was thinkin that this problem was dumb But it seems that we both have commited the same mistake.
Well i do have anothher way of sayin why its > 21/2
But that is really TEEEEEEEEEEEEDIOUS( beleive me Its a real tough eqn to solve) well lets just use continuity theorom and be satisfied with [21/2,2)
Anyways man thnx i am known for doing calculation mistakes but i never do logical errors,May be after a long time i have done it again in PHYSICS.I AM A PHYSICS FREAK
I may seem to be a very stupid girl because I could not understand the question itself . Can somebody explain me what the question is saying?