0.3 g of oxalate salt was dissolved in 100 ml solution. this solution requires 90 ml of N/20 KMnO4 for complete oxidation. the % of oxalate ion in salt is:
a) 33%
b) 66%
c) 70%
d)40%
milliequivalents of KMnO4 = 1/20 * 90 = 4.5 = millieq of oxalate salt
now millieq = n-factor * millimoles
so millimoles of oxalate are 2.25
hence mass of oxalate ion = 2.25 * 10-3 *88 = .198= 0.2
so percentage = 66 %
thanks