Hi, everyone
please can anyone prove the following:
xx yy >= xy yx where x and y are natural nos.
I hav done it, but i was not satisfied with my method , so please can anyone provide me an alternative.thanks, kvs!
what's wrong man this one's real easy ; 2 cases arise here eitheir both are equal or one being greater than the other.
without loss of generality suppose x>y the you an see that x^(x-y)>y^(x-y) hence by rearranging you have your answer