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Electrostatics

Electrostatics

by Ankul Garg -
Number of replies: 10
Find the electric potential at the apex of a cone whose curved surface (only) has surface charge density sigma. Slant height of cone is l and semi-vertical angle is theta.
In reply to Ankul Garg

Re: Electrostatics

by ishaan biswas -

well i ahvent solved the ques

but   the potential=sum(integral)of the potential due to the infinite rings (cut in the cone)

i ahd trubl with the integration tell me if u cud do it this way

In reply to ishaan biswas

Re: Electrostatics

by Ankul Garg -
That's ok. But i integrated the potential due to each ring at the apex of cone by taking dist. of a ring as x from the apex, and then putting limits from 0 to l*cos theta. But, in the soln. x is taken as the dist. of ring from apex along the slant ht. and then limits from 0 to l.
The two methods give different answers.
Now, i don't know what's wrong with my method.
In reply to Ankul Garg

Re: Electrostatics

by ishaan biswas -

in fact i had the same doubt while doing the derivations of rigid bodies....

but i culdn't figure out the problem wih this sol.

pleez tell me too if u  understand it

In reply to Ankul Garg

Re: Electrostatics

by Manish Verma -

Volume of the audio can be controlled from your system settings.  Try refreshing the page in case video does not show.

In reply to Manish Verma

Re: Electrostatics

by Ankul Garg -
Sir, I got ur point. Thnx very much. I was making the same mistake and i think its really a question to check our alertness.
Thnx very much.
In reply to Manish Verma

Re: Electrostatics

by ishaan biswas -

sir i still cannot view the video

there must be some problem

could you please explain me the concept

with regards

ishaan

In reply to Ankul Garg

Re: Electrostatics

by Shashank Todwal -

Is the ans K(sigma)(pie)lsin2(theta)

I did by integrating potential due to charges at the rings at a dist x along the curved area .

In reply to Shashank Todwal

Re: Electrostatics

by Ankul Garg -
The answer u got is wrong. It is [(sigma)lsin(theta)]/2€
Either u did the same mistake as i did or u integrated wrongly.
Just see the video as given by Manish Sir for this topic.