When a coil carrying steady current is short-circuited,the current becomes 1/n times initial current in time to.The time constant of the circuit is?
Ans:to/ln n
My Doubt:Steady current initially==> a DC source must be present, lets say cell of emf E.Resistance is ofcourse present.Now only inductor is shorted.So here we can't use the concept of decay of current wherein we assume that E is removed suddenly and we see the nature of i.Here E is not removed.But still the ans comes only by using this concept wherin we develop i=ioe-(R/L)t.PLz reply